# Acceleration Due to Gravity Definition

In physics, **gravity **is the **force that attracts** any **two objects** in the **universe**. At the same time, **acceleration **due to gravity is defined as the **change **in **velocity attained **by an **object **due to the **gravitational force** operating upon it. The SI unit used with the value of acceleration due to gravity is m/s^{2}. Whereas, the 6.674×10^{−11} Nm^{2}/kg^{2} is the value of the universal gravitational constant.

**Table of Contents**

## Formula of Acceleration Due to Gravity

If you want to calculate acceleration due to gravity, you can use the formula listed below or jump to our calculator to find your answer instantly.

g = GM/ r^{2}

**Where,**

G = universal gravitational constant (6.674×10^{−11} Nm^{2}/kg^{2})

M = Mass of earth

r = Radius of the earth

**Note:**

To know how to find out the acceleration due to gravity, you can use our Acceleration Due To Gravity Calculator.

### Example

If the moon's mass is 7.35 x 10^{22} kg, and a radius of the moon 1.7 x 10^{6} m , whereas the gravitational universal constant is 6.67 x 10^{-11} Nm^{2}/kg^{2} ,then find out the acceleration due to gravity at the Moon’s surface.

**Given data**

r = radius of the moon = 1.7 x 10^{6}m

M = moon's mass = 7.35 x 10^{22}k

G = gravitational universal constant = 6.67 x 10^{-11}Nm^{2}/kg^{2}

**To Find**

Acceleration due to gravity = ?

**Solution**

To find out the acceleration due to gravity on moon, we will use the formula listed below:

g = GM/r^{2}

Putting values in the formula:

g = (6.67 x 10^{-11}* 7.35 x 10^{22}) / (1.7 x 10^{6})^{2}= 16.19 x 10^{-1}= 1.62 g

The acceleration due to gravity on moon = **1.62 g**